Question

Can you please completely factor
`11 {x}^(2) + 24x + 1320`

Answer 1

`\begin{gathered} 11x^2+24+1320 \\ ax^2+bx+c=0 \\ \\ a=11\text{ b=24 and c=1320} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-24\pm\sqrt[]{24^2^{}-4*11*1320}}{2*11} \\ \\ x=\frac{-24\pm\sqrt[]{576^{}-58080}}{22} \\ \\ x=\frac{-24\pm\sqrt[]{-57504}}{22} \\ x=\frac{-24\pm\sqrt[]{-57504}}{22} \\ x=(-24\pm i239.8)/(22) \\ \\ x=(-24+i239.8)/(22)\text{ or }x=(-24-i239.8)/(22) \\ (x+(24-i239.8)/(22))(x+(24+i239.8)/(22)) \end{gathered}`