To find the length of the segment use the Pythagoras theorem below:

From the graph, we have:
AB = 15 - 3 = 12
BC = 7 - 2 = 5
Let's solve for the length of the segment AC:

Take the square-root of both sides:
![\begin{gathered} \sqrt[]{AC^2}=\sqrt[]{169} \\ \\ AC\text{ = 13} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p1vrimi0e39da8g6lojrnunbuan42324n6.png)
Therefore, the length of this segment is 13
ANSWER:
13