Question

Two 4-1 resistors are connected in parallel to a 12-V bat-tery. Use the fact that the voltage across each of the resis-tors is 12 V to find the total current through the battery.What single resistor, if connected to the battery alone(called the equivalent resistance), would draw this samecurrent?

Answer 1

Given data

*The given resistors are

`R_1=R_{2_{}}_{}_{}=4\text{ ohm}`

*The given battery voltage is V = 12 V

The equivalent resistance in parallel combination is calculated as

`\begin{gathered} R_(eq)=(R_1* R_2)/(R_1+R_2) \\ =(4*4)/(4+4) \\ =(16)/(8) \\ =2\text{ ohm} \end{gathered}`

The total current flows through the battery is calculated as

`\begin{gathered} I=(V)/(R_(eq)) \\ =(12)/(2) \\ =6\text{ A} \end{gathered}`