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(7 x 10^-5) x (5 * 10^-8)= ?x 10^

User Chasbeen
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1 Answer

6 votes

1) Let's calculate that. Start by multiplying the factors 7, and 5.


\begin{gathered} 7\cdot10^(-5)\text{ x 5 }\cdot10^(-8)= \\ 35\cdot10^(-13) \end{gathered}

After that, we use the property of the exponents when multiplying. Repeat the base and then add the exponents -8 + (-5) = -8 -5 = -13.

User Bob Risky
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