52.6k views
3 votes
A box contains letters, shown as MARCHING. What is the probability of the outcome in that order if letters are drawn one by one (a) with replacement? (b) without replacement?

User Coufu
by
7.5k points

1 Answer

6 votes

There are 8 letters in the word MARCHING.

So, the number of letters in the box, N=8

b)

The probabilty of drawing the first letter M is,


P(M)=(1)/(N)=(1)/(8)

If the letter is not replaced, the number of remaining letters in the box is 7.

So, the probabilty of drawing the second letter A is,


P(A)=(1)/(7)

Similarly, the probabilities of drawing letters R,C,H,I, N and G respectively is,


\begin{gathered} P(R)=(1)/(6) \\ P(C)=(1)/(5) \\ P(H)=(1)/(4) \\ P(I)=(1)/(3) \\ P(N)=(1)/(2) \\ P(G)=1 \end{gathered}

So, the probability of of the outcome in that order if letters are drawn one by one​ without replacement is,


undefined

User Diogo S
by
7.4k points