The formula for the monthly loan payment is given as
![A\text{ = }P((r(1+r)^n)/((1+r)^n-1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/a7rsmh2zim9zlck6k35c9pjun3bm6j13ab.png)
Where
P = loan amount ( initial principal) = $15000
A= Payment amount per period = ?
r = interest rate per period = (5/12) x (1/100) =0.0041667
n = total number of payments or periods = 4 years = 4 x 12 = 48 months
Substituting all these into the above equation gives
![A\text{ =15000( }(0.0041667(1+0.0041667)^(48))/((1+0.0041667)^(48)-1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/yrhfuh4sw7l27nc134lcjduv8gdq8fhcb2.png)
![A\text{ = 15000(}(0.0041667(1.0041667)^(48))/((1.0041667)^(48)-1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/7upje4jrt07tmqpn35x0a2aoba3sfx778j.png)
![\begin{gathered} A\text{ = }15000(\frac{0.0041667\text{ }*1.2208973}{1.2208973\text{ - 1}}) \\ A=\text{ 15000(}(0.005087112781)/(0.2208973)) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4jd0rm1lqgncqjloi4ehar1csyk476hkku.png)
![\begin{gathered} A=15000(0.023029311) \\ A=\text{ \$345.4396759} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ctyg29jwib7ksw1myzp4or1b8b68p7lx4d.png)
So each month he pays $345.44 to the nearest cent
B)
The total interest for the loan is given by
Total amount paid over the total period of time - Original amount borrowed
Total amount paid over the total period of time = 345.44 x 48 months = $16581.12
The total interest of the loan hence = $16,581.12 - $15,000 = $1,581.12
The total loan interest to the nearest cent = $1,581.12