The expression we have is:
![6x-2y=12](https://img.qammunity.org/2023/formulas/mathematics/college/l3yj55xeiz63vyf6o5w4nei0uhk4yn3bdr.png)
This is the equation of the line.
To find the y-intercept, we need to find the value for y, when x is equal to 0. So we plug x=0 into our equation:
![6(0)-2y=12](https://img.qammunity.org/2023/formulas/mathematics/college/oibzwefbtf4tdqbownqd6gq9ru6g9csy5w.png)
And we solve for y:
![-2y=12](https://img.qammunity.org/2023/formulas/mathematics/college/o6f1v55v4n69ngxap5dm05jtkbknedkxpu.png)
Divide both sides by -2:
![\begin{gathered} (-2y)/(-2)=(12)/(-2) \\ y=-6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vxs01fak9u0w7o0ldeenolg3anq0hraufz.png)
The y-intercept is at y=-6
In the coordinate form, the y-intercept is (0,-6)
Now, to find the x-intercept, we need to find the value of x, when y=0.
So we plug y=0 into the equation:
![6x-2(0)=12](https://img.qammunity.org/2023/formulas/mathematics/college/hkwx7250y6vna9zscr3k1mcw9nalvv2skj.png)
And we solve for x:
![6x=12](https://img.qammunity.org/2023/formulas/mathematics/college/xdxstc9wnf1mdqnrmsg5hcscro1nu6lf53.png)
Divide both sides by 6:
![\begin{gathered} (6x)/(6)=(12)/(6) \\ x=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jb9xvppblfn26l2n0ckejuv1vwk5ttkbpo.png)
The x-intercept is at x=2
In coordinate form, the x-intercept is: (2,0)