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What is the oxidation number of boron in Na{B(NO3)4}​

User Vivek Raja
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1 Answer

11 votes

Answer:

(+3)

Step-by-step explanation:

The oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as a hydride. Thus the oxidation state of boron in sodium boron hydride is (+3)

User Keryanie
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