Question

A store has 6 TV Graphic magazines and 8 News time magazines on the counter. If two customers purchased a magazine,find the probability that one each magazine was purchased

Answer 1

Case: Probability

Given:

Number of TV Graphic magazines = 6

Number of News time magazines = 8

Total number of magazines on the stand = 14.

*two customers purchased a magazine*

Required: find the probability that one each magazine was purchased

Method:

`\begin{gathered} Pr\left(one\text{ magazine each}\right? \\ =\text{ }(^(n1)C_(x1)*^(n2)C_(x2))/(^nC_x) \\ n1=\text{ number of TV graphic magazines} \\ x1=\text{ number of TV graphic magazines selected} \\ n2=\text{ number of News time magazines} \\ x2=\text{ number of News time magazines selected} \\ n=\text{ total number of magazines selected} \\ x=\text{ total number sslected} \end{gathered}`
`\begin{gathered} (^(n1)C_(x1)*^(n2)C_(x2))/(^nC_x) \\ (^6C_1*^8C_1)/(^(^14)C_2) \\ (6*8)/(91) \\ (48)/(91) \end{gathered}`

Final answer:

The probability that one each magazine was purchased is 48/91