Question

I need help with this practice problem solving The subject is pre trigonometry

Answer 1

`\theta=(2\pi)/(3)+\pi\cdot n`

Explanation:

Find the general solution for:

`\begin{gathered} 3\cot \theta=-\sqrt[]{3} \\ \text{ Divide both sides by 3} \\ \cot \theta=-\frac{\sqrt[]{3}}{3} \end{gathered}`

Now, for the general solution, it is known that for

`\begin{gathered} \cot ((\pi)/(6))=\sqrt[]{3} \\ \text{Then,} \\ \theta=(2\pi)/(3)+\pi\cdot n \end{gathered}`