Question

1. Smoesnail crawls at 3/25 m.p.h. At this rate, how far can he get in 1 2/3 hours?

Answer 1

`(1)/(5)\text{ miles}`

Step-by-step explanation:

Here, we want to get the distance the snail can go in the given time

Mathematically, we have it that:

`\text{Distance = sp}eed\text{ }*\text{ time}`

speed = 3/25 mph

Time = 1 2/3 hours = 5/3 hours

Thus, we have it that:

`\text{Distance = }(3)/(25)\text{ }*(5)/(3)\text{ = }(1)/(5)\text{ miles}`