Question

Find a quadratic function of the form y=ax^2 that passes through the point (-2,-8)

Answer 1

`\begin{gathered} \text{ since }y=ax^2 \\ \\ \text{ at }(-2,-8) \\ \\ \Rightarrow-8=a(-2)^2 \\ \\ \Rightarrow-8=a(4) \\ \\ \Rightarrow a=-(8)/(4)=-2 \\ \\ \Rightarrow y=-2x^2 \end{gathered}`

The quadratic equation is

`y=-2x^2`