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Find a quadratic function of the form y=ax^2 that passes through the point (-2,-8)

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Solution


\begin{gathered} \text{ since }y=ax^2 \\ \\ \text{ at }(-2,-8) \\ \\ \Rightarrow-8=a(-2)^2 \\ \\ \Rightarrow-8=a(4) \\ \\ \Rightarrow a=-(8)/(4)=-2 \\ \\ \Rightarrow y=-2x^2 \end{gathered}

The quadratic equation is


y=-2x^2

User Eelco
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