Question

what is the average rate of change f (t) t=0 t=236 seconds per second -36 feet per second -18 seconds per second 18 feet per second

Answer 1

`\begin{gathered} \text{average rate of change of f(t) = }(\Delta f)/(\Delta t)=(f(2)-f(0))/(2-0) \\ \text{From your question, I inferred that:} \\ f(2)\text{ = 36f}eet\text{ per second, and f(0) = 18f}eet\text{ per second} \\ \Rightarrow\text{ average rate of change of f(t) = }(36-18)/(2-0)=(18)/(2)=9fts^(-2) \end{gathered}`