Question

2. MGSE9-12.A.REI. 1 Which step in solving this equation is justified by the Distributive Property? Consider the sequence of steps to solve the equation: 6v + 3(v – 5) = 4v - (2v + 1) Given = 6v + 3(v — 5) = 4v - (2v + 1) Step 1 = 6 + 3x – 15 = 4y - (2v + 1) Step 2 => 6v + 3v – 15 = 4v – 2y = 1 Step 3 9v – 15 = 4y – 2y - 1 Step 4 => 9v - 15 -- 2v + 4y = 1 Step 5 =9v = 15 = 2y + 1 Step 6 3 7v - 15 =-1 Step 7 3 Tv = 14 Step 8 = v= 2 a. Step 1 b. Step 7 C. Step 5 d. Step 2

Answer 1

6v + 3(v – 5) = 4v - (2v + 1)

Given = 6v + 3(v — 5) = 4v - (2v + 1)

step 1

when you open the first parenthsesis in step 1

we have 6v + 3v - 15 = 4v - (2v + 1)

Then in step 2

we open the second parenthesis,

This gives;

6v + 3v - 15 = 4v - 2v - 1

Therefore; step 1 and step 2 justified the distributive property