Answer:
0.0000253moles
Explanations:
The decomposition of NI3 is given as shown below;
![2NI_3(s)→N_2(g)+3I_2(g)](https://img.qammunity.org/2023/formulas/chemistry/college/s0z19uot4frymz9mrk74exepdlsg43nj0j.png)
Given the following parameters
Mass of NI3 = 0.02 grams
Determine the moles of NI3
![\begin{gathered} moles\text{ of NI}_3=\frac{mass}{molar\text{ mass}} \\ moles\text{ of NI}_3=(0.02)/(394.719) \\ moles\text{ of NI}_3=0.0000507moles \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/33580nma9059p26srifnds90ifjuz1vab4.png)
Acoording to stochiometry, 2 moles of NI3 preoduces 1 mole of nitrogen. The mole of nitrogen produced is;
![\begin{gathered} mole\text{ of nitrogen}=(1)/(2)*0.0000597 \\ mole\text{ of nitrogen}=\text{0.0000253moles} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/qab8wc4vqewn1nr9dfvi8gc7atoys02swt.png)
Hence the moles of nitrogen produced is 0.0000253moles