Question

Question provided in picture only need assistance with part b

Answer 1

PART B

The probability is 1/2

STEP - BY - STEP EXPLANATION

What to find?

The probability of identical twins given that the twins consists of two boys.

Let A be the event of identical twins.

Let B be the event of having two boys as twins.

From the table given;

P(A) = 2/38

P(B)= 2/38

Recall the formula for a condititional probabibility

`P(A\text{ \backslash{}B)=}\frac{P(A\text{ n }B)}{P(B)}`

Note that:

P(A n B) =1/38

`P(A\text{ \backslash B) =}((1)/(38))/((2)/(38))`
`=(1)/(38)*(38)/(2)`
`=(1)/(2)`

Therefore, the probability of identical twins given that the twins consists of two boys is 1/2