An object is launched at a velocity of 20 m/s in a direction making an angle of 22° upward with the horizontal.What is the maximum height achieved by the projectile?

Question

asked Dec 20, 2023 45.5k views

1 Answer

Andre Cytryn · Answer 1 · 2023-12-25T14:49:35+0000

Given data:

Initial velocity,

$u=20\text{ m/s}$

Angle of projection,

$\theta=22\degree$

The maximum height achieved by the projectile is given as,

$H=(u^2\sin ^2\theta)/(2g)$

Here, g is the acceleration due to gravity.

Substituting all known values,

$\begin{gathered} H=\frac{(20\text{ m/s})^2*\sin ^2(22\degree)}{2*(9.8\text{ m/s}^2)} \\ \approx2.86\text{ m} \end{gathered}$

Therefore, the maximum height achieved by the projectile is 2.86 m.