20.6k views
0 votes
What is the product of the complex numbers below?(3 - 2i)(1 + 7i)A.-11 + 19iB.17 + 19iC.-11 - 23iD.17 - 23i

What is the product of the complex numbers below?(3 - 2i)(1 + 7i)A.-11 + 19iB.17 + 19iC-example-1

1 Answer

4 votes

Solution:

Given:


(3-2i)(1+7i)

To find the product, we multiply the terms in the second parentheses by each term in the first parentheses.

Thus, we have


\begin{gathered} 3(1+7i)-2i(1+7i) \\ open\text{ parentheses,} \\ 3+21i-2i-14i^2 \\ but\text{ i}^2=-1 \\ thus,\text{ we have} \\ 3+21i-2i-14(-1) \\ collect\text{ like terms,} \\ (3+14)+i(21-2) \\ \Rightarrow17+19i \end{gathered}

Hence, the product of the complex numbers is


17+19i

The correct option is B

User Frank Nielsen
by
4.6k points