Question

The specific heat capacity of steel is 450 J/kg°C. If heat is added to 2 kg of steel for 30seconds, raising its temperature from 10°C to 32°C, what is the heat flow rate? Express your answer in W.

Answer 1

Given:

The specific heat capacity of steel is

`c=\text{ 450 J/kg }^(\circ)C`

The mass of the steel is m = 2 kg

The initial temperature of steel is

`T_i=\text{ 10}^(\circ)\text{ C}`

The final temperature of steel is

`T_f\text{ = 32}^(\circ)C`

The time is t = 30 s

To find the heat flow rate.

Step-by-step explanation:

The heat flow rate can be calculated by the formula

`(Q)/(t)=(mc(T_f-T_i))/(t)`

On substituting the value, the heat flow rate will be

`\begin{gathered} (Q)/(t)=\text{ }(2*450*(32-10))/(30) \\ =\text{ 660 W} \end{gathered}`

Thus, the heat flow rate is 660 W.