Question

Point P is located 1.7 m from fixed point charge q. The electric field Ē at point P is 8.6 x

10-2 N/C, directed away from the point charge. What is the magnitude of q? Let the
electrostatic constant k = 8.99 x 10°N • m²/C2.
O
A. 2.8 10-11 C
0
B. 4.8 * 10-11 C
O.C. -4.8 x 10-11 C
D. 1.5 x 10-10

Answer 1

2.8 × 10^-11 C

Step-by-step explanation:

The computation of the magnitude of q is shown below;

The electric field at point P because of point charge Q is provided by,

E = 8.6 × 10^-2 N/C

And, the separation between charge Q and P is r = 1.7m

Now According to the Coulomb's law,

E = kQ ÷ r²

8.6 × 10^-2 = 9 × 10^9 × Q ÷ (1.7)²

8.6 × 10^-2 × 2.89 ÷ 9 × 10^9 = Q

Q = (8.6 × 2.89 ÷ 9) × 10^-11

Q = 2.76 × 10^-11 C

= 2.8 × 10^-11 C