Answer:
10
Explanation:
Given that:
Let :
C = chemistry
B = biology
P = physics
n(C) = 18
n(P) = 20
n(B) = 15
C only = 2
P only = 8
B only = 1
All 3 subjects = 4
P n B only = 20 - (8 + x + 4) = 8 - x
C n B only = 18 - (2 + x + 4) = 12 - x
B = (12 - x) + 4 + 1 + (8 - x) = 15
B = 25 - 2x = 15
B = 10= 2x
x = 5
PnC only, x = 5
Number who chose none of the 3 subjects, k equals :
2 + x + 8 + 4 + 1 + (8 - x) + (12 - x) + n = 40
35 - 3x + n = 40
x = 5
35 - 15 + y = 40
20 + n = 40
n = 40 - 20
n = 10