(0,3509)
(1,3468)
(3,3386)
(7,3222)
(9,3140)
h=3509-41x
Step-by-step explanation
Step 1
as we can see, the independent quantity is the time , and the dependent quantity is the heigth because it depends on the time.
then when time = o, t=o
![0\Rightarrow3509\text{ ft}](https://img.qammunity.org/2023/formulas/mathematics/college/ptvnpsslrqq0bqifzw9jzjtr6l56n8wnha.png)
after 1 minute the helicopter has descended 41 ft, then
when time = 1, t=1
![\begin{gathered} heigth_1=3509-(1\cdot41) \\ heigth_1=3509-41 \\ heigth_1=3468 \\ (1,3468) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jb908r8b04llmo2wkbcvc4xafgq00prfn2.png)
when t=3
![\begin{gathered} heigth_3=3509-(3\cdot41) \\ heigth_3=3509-123 \\ heigth_3=3386 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pev35w8b1pxx41a95ybxaeymo0tioub3m9.png)
when heigth=3222
![\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ 3222=3509-41x \\ \text{subtract 3509 in both sides} \\ 3222-3509=3509-41x-3509 \\ -287=-41x \\ \text{divide both sides by -41} \\ (-287)/(-41)=(-41x)/(-41) \\ 7=x \\ \text{hence}(7,3222) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/b3oe0ffnjtbvngl0b87ncy3wkovlh3m4qk.png)
when heigth=3140
![\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ \text{3140}=3509-41x \\ subtract\text{ 3509 in both sides} \\ \text{3140-3509}=3509-41x-3509 \\ -369=-41x \\ \text{divide both sides by -41} \\ (-369)/(-41)=(-41x)/(-41) \\ 9=x \\ x=9,\text{then} \\ (9,3140) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5qjxlsqibmumdil3kppm7qlkif15oowjqw.png)
Step 2
now, the equation is
![\begin{gathered} \text{Heigth}=3509-41x \\ h=3509-41x \\ \text{where} \\ h\text{ is the heigth in ft and t is the time in minutes} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k8ycx2a1wvau2tfgfr5650aklt12b4p30m.png)
I hope this helps you