Solution:
Given that John wishes to build a square fence with an area of 121 square yards, as shown below:
The area of a square is expressed as

Given that the area of the square fence is 121 square yards, this implies that

The perimeter of a square is expressed as

Thus, the perimeter of the fence is evaluated by substituting the value of 11 for L into the perimeter formula.

Hence, the perimeter of the fence is 44 yards.