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A veterinarian is enclosing a rectangular outdoor running area against his building for the dogs he cares for (see image). He wants to maximize the area using 108 feet of fencing.

A veterinarian is enclosing a rectangular outdoor running area against his building-example-1

1 Answer

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ANSWER

The width that will give the maximum area is 27 feet. The maximum area is 1458 square feet.

Step-by-step explanation

The equation that gives the area is a quadratic function,


A(x)=x(108-2x)

To find the width that maximizes the area, we have to find the x-coordinate of the vertex of this parabola. We can observe in the equation that the leading coefficient is -2, so the vertex is the maximum.

First, apply the distributive property to write the equation in standard form,


A(x)=-2x^2+108x

The x-coordinate of the vertex of a parabola if the equation is in standard form is,


\begin{gathered} y=ax^2+bx+c \\ \\ x_(vertex)=(-b)/(2a) \end{gathered}

In this case, b = 108 and a = -2,


x_(vertex)=(-108)/(-2\cdot2)=(108)/(4)=27

Hence, the width that will give the maximum area is 27 feet.

To find the maximum area, we have to find A(27),


A(27)=27(108-2\cdot27)=27(108-54)=27\cdot54=1458

Hence, the maximum area is 1458 square feet.

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