Given
First : They assembled 20 regular wreaths and 16 deluxe wreaths, which used a total of 140 pinecones
Let's represent regular wreaths with r
and
Let's represent deluxe wreaths with d

Second: They assembled 20 regular wreaths and 18 deluxe wreaths, using a total of 150 pinecones

We now have

we can now solve simultaneously, by subtracting the equation 1 and 2

We can subsitute d=5 in equation 1 or 2

The final answer
5 pinecones on the deluxe wreath and 3 pinecones on the regular wreath