Question

3. Identify the zeros of the equation below: 2x^2 + 23 = 14x

Answer 1

Simplify the equation.

`\begin{gathered} 2x^2+23=14x \\ 2x^2-14x+23=0 \end{gathered}`

Determine the zeros of the equation by using quadratic formula.

`\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ =\frac{14\pm\sqrt[\square]{(-14)^2-4\cdot2\cdot23}}{2\cdot2} \\ =\frac{14\pm\sqrt[]{12}}{4} \\ =\frac{2(7\pm\sqrt[]{3})}{4} \\ =(7)/(2)\pm\frac{\sqrt[]{3}}{2} \end{gathered}`

THus zeros of the equation is,

`(7)/(2)+\frac{\sqrt[]{3}}{2}`

and

`(7)/(2)-\frac{\sqrt[]{3}}{2}`