Question

Factor by grouping c^2-8c +16 -4d^2

Answer 1

INFORMATION:

We have the following expression

`c^2-8c+16-4d^2`

And we must factor it by grouping

STEP BY STEP EXPLANATION:

To factor it by grouping, we must:

1. group the first 3 terms of the expression

`(c^2-8c+16)-4d^2`

2. factor the expression in the parenthesis

`(c-4)^2-4d^2`

3. rewrite 4d^2 as unique exponential expression

`(c-4)^2-(2d)^2`

4. factor by square difference

`((c-4)+2d)((c-4)-2d)`

5. simplify

`=(c+2d-4)(c-2d-4)`

ANSWER:

the factoring for c^2-8c +16 -4d^2 by grouping is

`(c+2d-4)(c-2d-4)`