Question

In the equation 2KClO3-> 2KCl+3O2 how many many miles of potassium chloride are produced alongside 0.85 moles of oxygen gas

Answer 1

We first verify that the reaction equation is balanced. To do this we have the atoms of each element on each side of the reaction. we have 2 potassium atoms, 2 chlorine atoms, and 6 oxygen atoms on each side of the reaction. So the equation is balanced.

Now, by stoichiometry we can find the moles of KCl. The KCl to O2 ratio is 2/3 so the moles of KCl will be:

`\begin{gathered} MolKCl=givenmolO_2*(2molKCl)/(3molO_2) \\ MolKCl=0.85molO_2*(2molKCl)/(3molO_2)=0.57molKCl \end{gathered}`

The moles of potassium chloride produced is 0.57mol KCl