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Find the center and radius of the circle: x² + y² - 2x + 4y = -1

User Enle Lin
by
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1 Answer

6 votes

We need to complete the perfect square in x and y, that is,


x^2-2x=(x-1)^2-1

and


y^2+4y=(y+2)^2-4

Then, our given equation can be rewritten as:


(x-1)^2-1+(y+2)^2-4=-1

which is equal to


\begin{gathered} (x-1)^2+(y+2)^2-5=-1 \\ \end{gathered}

By moving -5 to the right hand side, we have


\begin{gathered} \mleft(x-1\mright)^2+\mleft(y+2\mright)^2=-1+5 \\ \mleft(x-1\mright)^2+\mleft(y+2\mright)^2=4 \\ \mleft(x-1\mright)^2+\mleft(y+2\mright)^2=2^2 \end{gathered}

Since the general circle equation is


\mleft(x-h\mright)^2+\mleft(y-k\mright)^2=r^2

then, the answer is:


(x-1)^2+(y+2)^2=2^2

then, the center is (h,k)= (1, -2) and the radius is r=2

User Jenorish
by
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