Given:
Principal, P=$3000
Interest rate, r=0.052
Years, t=3 years
To find the return amount is compounded monthly:
Using the formula,
![\begin{gathered} A=P(1+(r)/(12))^(12t)_{} \\ =3000(1+(0.052)/(12))^(12*3) \\ =3000(1+0.00433)^(36) \\ =3505.30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/317cbpp2qdwkpfa5rpzypjpq09nzvudz13.png)
Hence, the return amount on investment is $3505.30.
In percentage,
The return on investment is,
![\begin{gathered} (3505.3)/(3000)*100=16.84 \\ \approx16.8\text{ \%} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/foi3f96hekak976nbfm57i4vhhtlh03eg8.png)
Hence, the answer is 16.8%.