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write in slope intercept form and identity the slope and y intercept. a. x/3 + y/2 = 1b. 4x -3y + 2 =0c. x - y = 5(x - y)

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Consider that the slope-intercept form of the straight line with slope (m) and y-intercept (c) is given by,


y=mx+c

a.

Modify the given equation as,


\begin{gathered} (x)/(3)+(y)/(2)=1 \\ (y)/(2)=-(x)/(3)+1 \\ y=-(2)/(3)x+2 \end{gathered}

Thus, the equation in slope-intercept form can be written as,


y=-(2)/(3)x+2

b.

Modify the given equation as,


\begin{gathered} 4x-3y+2=0 \\ 3y=4x+2 \\ y=(4)/(3)x+(2)/(3) \end{gathered}

Thus, the equation in slope-intercept form can be written as,


y=(4)/(3)x+(2)/(3)

c.

Modify the given equation as,


\begin{gathered} x-y=5(x-y) \\ x-y=5x-5y \\ 5y-y=5x-x \\ 4y=4x \\ y=x \end{gathered}

Thus, the equation in slope-intercept form can be written as,


y=x

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