Question

Find the capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm.Group of answer choices2.8x10-10 F1.0x10-6 F2.8x10-12 F2.0x10-5 F

Answer 1

Given the area is:

A=4.0 cmx4.0 cm

The seperation distance is d=5.0 mm

The capacitance is :

`\begin{gathered} C=(\epsilon_oA)/(d) \\ \Rightarrow C=8.85*10^(-12)(4.0*10^(-2)*4.0*10^(-2))/(5*10^(-3)) \\ \Rightarrow C=2.83*10^(-12)F \end{gathered}`

Thus the answer is

`2.8*10^(-12)F`