Question

Can you help me with this, I’ve already completed the assignment but trying to go back and figure out what I missed and what I did wrong

Answer 1

OK

the base in this case is an hexagone

we can find the area of the base with the following formula

`A=(3√(3)S^2)/(2)`

where S represent the side of the hexagone

s=20

`A=(3√(3)*20^2)/(2)`
`A=600√(3)=1039.23`

Perimiter is given by 6*S

P=6*20=120

h=22

Given the following formula for the hexagone

`A=(p*a)/(2)`

`600√(3)=(120*a)/(2)`

solving for a

`a=(2*600√(3))/(120)=10√(3)=17.32`

applying pythagoras theorem

`l^2=a^2+h^2`
`l^2=(10√(3))^2+22^2`
`l=√(784)=28`

Lateral surface

`LS=(p*l)/(2)`
`LS=(120*28)/(2)=1680`

Total surface

`TS=LS+A`
`TS=1680+600√(3)`
`TS=2719.23048`

Volume

`V=(1)/(3)A*h`
`V=(1)/(3)600√(3)*22`
`V=4400√(3)=7621.02`