EXPLANATION :
From the problem, we have a linear function :
![y=(1)/(2)x-4](https://img.qammunity.org/2023/formulas/mathematics/college/y2ytz8l9mx6mae1u2thzqasb7oudix2wty.png)
We need 2 points to graph this function.
when x = 0 :
![\begin{gathered} y=(1)/(2)(0)-4 \\ y=-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3hs8pr3d6tnbqtxrb70z6lywtwvrcdlhfn.png)
when x = 2
![\begin{gathered} y=(1)/(2)(2)-4 \\ y=-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/79t0l76htuq19l8o0ys71l5p5v0ogph5tv.png)
Plot the points (0, -4) and (2, -3)
Since the function is a continuous line, the domain and range are all real numbers.
Domain = (-∞, ∞)
Range = (-∞, ∞)
and since the graph is a line with a defined slope, this is a function