Given data
*The given horizontal piper of diameter is D = 3.0 cm = 0.03 m
*The given depth is d = 5.0 m
*The given water desnsity is

(a)
The magnitude of the frictional force between the plug and pipe wall is given as

*Here r = d/2 is the radius
Substitute the values in the above expression as

(b)
The volume flow rate is calculated as
![\begin{gathered} V=Av \\ =\pi r^2\sqrt[]{2gd} \\ =3.14*((0.03)/(2))^2*\sqrt[]{2*9.8*5.0} \\ =6.99*10^(-3) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/ie5vbx0t1gfmy38hyefku0e3oucyacb98m.png)
The total volume is calculated as
