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At a restaurant, the choices for hamburger toppings are cheese, tomato, lettuce,onion, mayo, mustard, ketchup and pickles. If you choose 5 toppings, how manyways can you pick your toppings?(Hint: Is this a combination or permutation?)

User Hamstu
by
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1 Answer

3 votes

at the restauant we can choose 5 topping for a hamburger,

let us solve using combination,


^5C_0+^5C_1+^5C_2+^5C_3+^5C_4+^5C_5=

we know that,


^nC_0+^nC_1+^nC_2+\ldots+^nC_5=2^n

thus,


\begin{gathered} ^5C_0+^5C_1+^5C_2+^5C_3+^5C_4+^5C_5=2^5 \\ =32 \end{gathered}

hence, there are 32 ways to pick the toppings.

User Deckerz
by
7.7k points
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