Question

Given the equation of the circle, identify the center and radius (x + 1) ^ 2 + (y - 1) ^ 2 = 36

Answer 1

The form of the equation of the circle is

`(x-h)^2+(y-k)^2=r^2`

(h, k) is the center

r is the radius

Let us compare it with the given equation to find the center and the radius

`(x+1)^2+(y-1)^2=36`

From the comparing

h = -1

k = 1

r^2 = 36

Find the square root of 36 to get r

`\begin{gathered} r=\sqrt[]{36} \\ r=6 \end{gathered}`

The center is (-1, 1) and the radius is 6