Question

State the equation of the axis of symmetry of the function f(x) = 3x^2 + 6x - 2

Answer 1

The given function is:

`f(x)=3x^2+6x-2`

Complete the square and factor as follows:

`\begin{gathered} f(x)=3(x^2+2x+1)-2-3 \\ f(x)=3(x+1)^2-5_{} \end{gathered}`

Compare with:

`f(x)=a(x-h)^2+k`

To get:

`(h,k)=(-1,-5)`

Since the parabola is vertical the axis of symmtery is vertical which is x=-1.