ANSWER:
The maximun velocity is 16.07 m/s
At x = 0.26
The velocity is 8.36 m/s
The accelearion is 286.67 m/s^2
The resorting force is 86 N
Explanation:
Given:
k = 310 N / m
Max distance = 0.5 m
Mass of block = 0.3 kg
Max velocity:
Using conservation of energy:
![\begin{gathered} (1)/(2)kx^2=(1)/(2)mv^2 \\ v^2=(kx^2)/(m) \\ \text{ replacing} \\ v^2=(310\cdot0.5^2)/(0.3) \\ v=\sqrt[]{258.33} \\ v=16.07\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/w289lpu2kr4310t86nmxuri6f2m0sourhr.png)
At x = 0.26 m:
![\begin{gathered} v^2=(kx^2)/(m) \\ v^2=(310\cdot0.26^2)/(0.3) \\ v=\sqrt[]{69.85} \\ v=8.36\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/il8ugaikm2j7ly7tpqfh39zs5jrenpinwc.png)
Acceleration:

The resorting force:
