1 Answer

Mohd Asim · Answer 1 · 2023-08-26T18:55:08+0000

For a function of the form:

$y=acos(b\theta)$

a = amplitude = 2

b = angular frequency = 1/4

The period can be calculated as follows:

$\begin{gathered} T=(2\pi)/(b) \\ So: \\ T=(2\pi)/(1/4) \\ T=8\pi \end{gathered}$

Now, we can graph the function easily:

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