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Write parallel and perpendicular equation thru (-3,5) y=2/3x + 1

User Tyshan
by
4.7k points

1 Answer

3 votes

Answer:

Explanation:

1 Simplify (-3,5)y(−3,5)y to -3,5y−3,5y.

-3,5y=\frac{2}{3}x+1

−3,5y=

3

2

x+1

2 Simplify \frac{2}{3}x

3

2

x to \frac{2x}{3}

3

2x

.

-3,5y=\frac{2x}{3}+1

−3,5y=

3

2x

+1

3 Switch sides.

\frac{2x}{3}+1=-3,5y

3

2x

+1=−3,5y

4 Break down the problem into these 2 equations.

\frac{2x}{3}+1=-3

3

2x

+1=−3

\frac{2x}{3}+1=5y

3

2x

+1=5y

5 Solve the 1st equation: \frac{2x}{3}+1=-3

3

2x

+1=−3.

x=-6

x=−6

6 Solve the 2nd equation: \frac{2x}{3}+1=5y

3

2x

+1=5y.

x=\frac{3(5y-1)}{2}

x=

2

3(5y−1)

7 Collect all solutions.

x=-6,\frac{3(5y-1)}{2}

x=−6,

2

3(5y−1)

User Oreopot
by
5.6k points