Question

A compound contains 36%. Of calcium and 64% of chlorine. Calculate its simplest

formula (Ar of Ca : 40, Ar of CI . 35.5).

Explain please , ASAP

Answer 1

Step-by-step explanation:

1. Find the empirical formula of a compound that has 36% of Calcium (Ca), 64% of Chlorine (Cl).

2. Find molar mass of each component: Ca=40.078, Cl=35.453

3 Convert to moles: Ca=0.8982484155896, Cl=1.8052068936338

4 Find smallest mole value: 0.8982484155896

5 Divide all components by the smallest value: Ca=1, Cl=2.0096967189738

6 Round to closest whole numbers: Ca=1, Cl=2

7 Combine to get the empirical formula: CaCl2