Question

Find the coordinates of the vertices of the figure after the given transformation: T<2,4> translation 3A. J′(1,−1),E′(1,1),V′(4,3)B. J′(0,−2),E′(0,0),V′(3,2)C. J′(−2,−1),E′(−2,1),V′(1,3)D. J′(−3,−2),E′(−3,0),V′(0,2)

Answer 1

According to the given rule of transformation, any point (x,y) is transformed as follows:

`(x,y)\rightarrow(x+2,y+4).`

Now, the coordinates of the vertices of the triangle are:

`V(-1,-1),J(-4,-5),E(-4,-3).`

Therefore:

`\begin{gathered} V^(\prime)(-1+2,-1+4), \\ J^(\prime)(-4+2,-5+4), \\ E^(\prime)(-4+2,-3+4). \end{gathered}`

Simplifying the above result, you get:

`J^(\prime)(-2,-1),E^(\prime)\left(−2,1\right),V^(\prime)\left(1,3\right).`

Answer:

`J^(\prime)(-2,-1),E^(\prime)(-2,1),V^(\prime)(1,3).`