Question

I really need help solving this, struggling with it this is a problem from my ACT prep guide It is trigonometry

Answer 1

For this case we can do the following:

`(\tan(-(2\pi)/(3)))/(\sin((7\pi)/(4)))-\sec (-\pi)=\frac{-\sqrt[]{3}}{\frac{\sqrt[]{2}}{2}}-(-1)=\frac{2\sqrt[]{3}}{\sqrt[]{2}}+1=-\sqrt[]{2}\cdot\sqrt[]{3}+1=-\sqrt[]{6}+1`