Question

11) -3(1 + 6r) = 14 - r

Answer 1

`-3(1+6r)=14-r`

Distributing over parentheses,

`\begin{gathered} -3\cdot1+(-3)\cdot6r=14-r \\ -3-18r=14-r \end{gathered}`

Adding r at both sides,

`\begin{gathered} -3-18r+r=14-r+r \\ -3-17r=14 \end{gathered}`

Adding 3 at both sides,

`\begin{gathered} -3-17r+3=14+3 \\ -17r=17 \end{gathered}`

Dividing by -17 at both sides,

`\begin{gathered} (-17r)/(-17)=(17)/(-17) \\ r=-1 \end{gathered}`