We have to add the areas from A to F.
We then can write:
![S=A+B+C+D+E+F](https://img.qammunity.org/2023/formulas/mathematics/college/7nq0wz457iir3415yc3wn5vg72uhlvre3a.png)
As each area is a rectangle, the area is the product of the sides.
We can also simplify and see that:
![A=E=16\cdot13=208](https://img.qammunity.org/2023/formulas/mathematics/college/utf1f22qfva77e5szqqsqi7rfwddzgtvio.png)
![B+C+D+F=25\cdot(13+16+13+16)=25\cdot58=1450](https://img.qammunity.org/2023/formulas/mathematics/college/8f9ohkvs5xjbqlztgavd3gtvhxtawlidig.png)
Then:
![\begin{gathered} S=A+(B+C+D+F)+E \\ S=208+1450+208 \\ S=1866in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gcuzjludq6if3po9tb0bqenm92o3m40huu.png)
The surface of one chest is 1866 square inches.
The four chests will represent:
![4\cdot1866=7464in^2](https://img.qammunity.org/2023/formulas/mathematics/college/zuoo41kd4a0r30w8oedpx4dtp8ktazrgfw.png)
If each can paints 933 square inches, she will need:
![(7464)/(933)=8\text{ cans}](https://img.qammunity.org/2023/formulas/mathematics/college/umw61adlj5473bsmcapmlrle1bama38s0b.png)
Answer:
Each chest has a surface of 1866 sq. in.
The four chest represent 7464 sq. in. of surface area.
She needs 8 cans of paint to paint all 4 chests.