Question

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Answer 1

Given:

`(3-4i)(6i+7)-(2-3i)`

1. Arrange the expression, with the variables are written first

`(-4i+3)(6i+7)-(-3i+2)`

2. Distribute the "minus" operation

`(-4i+3)(6i+7)+3i-2`

3. Expand by multiplying the first two expressions

`(-4i+3)(6i+7)`

*multiply the first terms

`(-4i)(6i)=-24i^2`

*multiply the outer terms

`(-4i)(7)=-28i`

*multiply the inner terms

`(3)(6i)=18i`

*multiply the last terms

`(3)(7)=21`

This will give us:

`(-24i^2-28i+18i+21)`

*combine like terms

`(-24i^2-10i+21)+3i-2`

*Remove the parenthesis

`-24i^2-10i+21+3i-2`

4. Combine like terms

`-24i^2-7i+19`

The final answer would be:

`-24i^2-7i+19`