Answer:
The coordinate of the initial point is given below as
![(x_1,y_1)\Rightarrow(9,3)](https://img.qammunity.org/2023/formulas/mathematics/high-school/rc0ggak2s3n68vrqguczmqha93287o5zw5.png)
The coordinate of the terminal point is
![(x_2,y_2)\Rightarrow(16,12)](https://img.qammunity.org/2023/formulas/mathematics/high-school/15aq5yp07zzu5o6k3obafy0j5a51fykiue.png)
Concept:
The formula below will be used to calculate a linear form of v
![\Rightarrow(x_2-x_1)i+(y_2-y_1)j_{}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gp2shw10nqebcc8qqta72iz3oo1b1tjfy9.png)
By substituting the values, we will have
![\begin{gathered} \Rightarrow(x_2-x_1)i+(y_2-y_1)j_{} \\ \Rightarrow(16-9)i+(12-3)j \\ \Rightarrow7i+9j \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/zo4x4htvr0p4lb4dlip0arjrowq2hxquw3.png)
Hence,
The final answer is
![v=7i+9j](https://img.qammunity.org/2023/formulas/mathematics/high-school/8fb7mk52xel8if6tw0pqpbyc9wk8lhxr6r.png)
The FIRST OPTION is the right answer