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What is the center and radius for the circle with equation (x-2)^2 + (y-5)^2=49

User Ben Childs
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1 Answer

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Solution

For this case we have the following equation given by:


(x-2)^2+(y-5)^2=49

The general equation of a circle is given by:


(x-h)^2+(y-k)^2=r^2

And for this case by direct comparison we have:


r^2=49

Then we have:


r=\sqrt[]{49}=7

And the center si given by C=(h,k)

From the equation given we have:


C=(2,5)

User Butallmj
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