Given:
The total number of seats, T=750.
Let x be the number of seats in a row and y be the number of rows.
It is given that the number of seats in a row is 5 less than the number of rows.
Hence, the number of seats in a row can be expressed as,

Now, expression for the total number of seats can be given by,

Plug in x=y-5 and T=750 in the above equation and simplify.

The equation (1) is in the form of a quadratic equation of the form,

Comparing equations (1) and (2), a=1, b=-5 and c=-750.
Now, using discriminant method, the solution of y can be expressed as,
![\begin{gathered} y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y=\frac{-(-5)\pm\sqrt[]{(-5)^2-4*1*(-750)}}{2*1} \\ y=\frac{5\pm\sqrt[]{25+3000}}{2*1}\text{ } \\ y=\frac{5\pm\sqrt[]{3025}}{2} \\ y=(5\pm55)/(2)\text{ } \\ y=(5+55)/(2)\text{ or y=}(5-55)/(2) \\ y=(60)/(2)\text{ or y=}-(50)/(2) \\ y=30\text{ or y=-25} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/68fvbxlag1rnvhssopdvh5zub3gzscrt48.png)
Since the number of rows cannot be negative, y=30.
Put y=30 in equation (a) to find x.

Therefore, the number of seats in a row is 25.